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VIDEO ANSWER: In this problem, the equilibrium mixture at 875, we're told, contains the following. NH3, N2, and H2. And this is 1 .46 times 10 to the minus fifth molar. And my N2 is 1 .57 times 10 to the minus second molar. and my H2 is 1 .13 times
LTI LaunchOWLv2 | Online teaching andprod04-cnow-owl.cengagenow.com/ilrn/takeAssignment/takePress(fn) Fto exit full screent-takeTheme 8 - Chemical Kinetics OWLS[Review Topics][References]1. Reaction R.Use the References to access important values if needed for this question.2. Activation ..3. Calculate ..4. Factors Aff..5. Writing Eq...6. Writing Eq...7. Equilibrium..QuestionQuestionQuestion8. The Sig...9. Le Chat...2reo10. Le Cha...2reo11. Le Cha...2reo12. Le Cha..2reo13. Effect . 2recProgress:7/14 groupsDue Apr 29 at 11:55 PMConsider the following equilibrium system at 875  K. 2 NH3( g) ⇄N2( g)+3 H2( g)If an equilibrium mixture of the three gases at 875  K contains 1.46 × 10^-5MNH3, 1.57 × 10^-2MN2, and 1.13 × 10^-2MH2, what is the value of the equilibrium constant K ? K=□Submit AnswerRetry Entire Group8 more group attempts remaining8 more group attempts remaining